Example XMPP stanza

mfoss — Fri, 20 Mar 2009 01:47:51 +0000

dawit wrote:

I though it is possible to discover information about a public room without having to actually joining the room.

Yes, it is possible:

<iq to='testroom@conference.localhost' type='get'>
  <query xmlns='http://jabber.org/protocol/disco#items'/>
</iq>
<iq from='testroom@conference.localhost' type='result' to='badlop@localhost/Tka'>
  <query xmlns='http://jabber.org/protocol/disco#info'>
    <identity name='My room name' type='text' category='conference'/>
    <feature var='http://jabber.org/protocol/muc'/>
    <feature var='muc_public'/>
    <feature var='muc_persistent'/>
    <feature var='muc_open'/>
    <feature var='muc_semianonymous'/>
    <feature var='muc_moderated'/>
    <feature var='muc_unsecured'/>
    <x xmlns='jabber:x:data' type='result'>
      <field var='FORM_TYPE' type='hidden'>
        <value>http://jabber.org/protocol/muc#roominfo</value>
      </field>
      <field label='Room description' var='muc#roominfo_description'>
        <value>My room description</value>
      </field>
      <field label='Number of occupants' var='muc#roominfo_occupants'>
        <value>1</value>
      </field>
    </x>
  </query>
</iq>

dawit wrote:

If I could not get information such as how many occupants a room has and stuff like that, is there a way to join a room on "INVISIBLE" mode?

No, that is not possible.

ejabberd - Comments for "Room Information discovery problem."

Example XMPP stanza